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	<title>Comments on: The Hasse derivative, part II: Multivariate partial Hasse derivatives.</title>
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	<link>http://math.fontein.de/2009/10/02/the-hasse-derivative-part-ii-multivariate-partial-hasse-derivatives/</link>
	<description>Focussed on, but not limited to Computational Number Theory</description>
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		<title>By: Felix Fontein</title>
		<link>http://math.fontein.de/2009/10/02/the-hasse-derivative-part-ii-multivariate-partial-hasse-derivatives/comment-page-1/#comment-61</link>
		<dc:creator>Felix Fontein</dc:creator>
		<pubDate>Mon, 05 Oct 2009 17:02:52 +0000</pubDate>
		<guid isPermaLink="false">http://math.fontein.de/?p=474#comment-61</guid>
		<description>Ah, I think this is just a problem with notation. When I wrote, &#8220;&lt;i&gt;homomorphism of unitary commutative rings&lt;/i&gt;&#8221;, I assumed that the homomorphism satisfies $\varphi(1_R) = 1_{R&#039;}$. :-) I think I have to make it a bit more clearly, to make it less confusing... Thanks for the hint!</description>
		<content:encoded><![CDATA[<p>Ah, I think this is just a problem with notation. When I wrote, &ldquo;<i>homomorphism of unitary commutative rings</i>&rdquo;, I assumed that the homomorphism satisfies <img src='http://math.fontein.de/wp-content/latex/129/129b1df0aa68f7cdab5e685eb4bc5b29-T-000000-0.png' alt='\varphi(1_R) = 1_{R&#039;}' title='\varphi(1_R) = 1_{R&#039;}' class='latex-inline' />. :-) I think I have to make it a bit more clearly, to make it less confusing&#8230; Thanks for the hint!</p>
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		<title>By: Alexey Maevskiy</title>
		<link>http://math.fontein.de/2009/10/02/the-hasse-derivative-part-ii-multivariate-partial-hasse-derivatives/comment-page-1/#comment-60</link>
		<dc:creator>Alexey Maevskiy</dc:creator>
		<pubDate>Mon, 05 Oct 2009 14:19:34 +0000</pubDate>
		<guid isPermaLink="false">http://math.fontein.de/?p=474#comment-60</guid>
		<description>Hello! Thank you for this excellent article! I think it will be useful for many peoples.
But I note that in the first proposition it is necessary to add one of the following constraints on the ring homomorphism: $\varphi(1_R)=1_{R&#039;}$ or $\varphi^*(x) = \varphi(1_R)x$. If both requirements does not hold its easy to make a counterexample for situation when proposition is false ($\varphi:Z_{10}\rightarrow Z_{10}$, $\varphi(a)=6a$).</description>
		<content:encoded><![CDATA[<p>Hello! Thank you for this excellent article! I think it will be useful for many peoples.<br />
But I note that in the first proposition it is necessary to add one of the following constraints on the ring homomorphism: <img src='http://math.fontein.de/wp-content/latex/7c2/7c20923af8909cea076d24e1b532e162-T-000000-0.png' alt='\varphi(1_R)=1_{R&#039;}' title='\varphi(1_R)=1_{R&#039;}' class='latex-inline' /> or <img src='http://math.fontein.de/wp-content/latex/edd/edd1c6ba43d05e688312e781b559a146-T-000000-0.png' alt='\varphi^*(x) = \varphi(1_R)x' title='\varphi^*(x) = \varphi(1_R)x' class='latex-inline' />. If both requirements does not hold its easy to make a counterexample for situation when proposition is false (<img src='http://math.fontein.de/wp-content/latex/a16/a1602d35c82dd5581f38d5291946d0e0-T-000000-0.png' alt='\varphi:Z_{10}\rightarrow Z_{10}' title='\varphi:Z_{10}\rightarrow Z_{10}' class='latex-inline' />, <img src='http://math.fontein.de/wp-content/latex/b92/b92979ea572bcd0e2867f65450a455b0-T-000000-0.png' alt='\varphi(a)=6a' title='\varphi(a)=6a' class='latex-inline' />).</p>
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